b^2-4b+1=-5

Solution for b^2-4b+1=-5 equation:

Simplifying
b2 + -4b + 1 = -5

Reorder the terms:
1 + -4b + b2 = -5

Solving
1 + -4b + b2 = -5

Solving for variable 'b'.

Reorder the terms:
1 + 5 + -4b + b2 = -5 + 5

Combine like terms: 1 + 5 = 6
6 + -4b + b2 = -5 + 5

Combine like terms: -5 + 5 = 0
6 + -4b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-6' to each side of the equation.
6 + -4b + -6 + b2 = 0 + -6

Reorder the terms:
6 + -6 + -4b + b2 = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -4b + b2 = 0 + -6
-4b + b2 = 0 + -6

Combine like terms: 0 + -6 = -6
-4b + b2 = -6

The b term is -4b.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4b + 4 + b2 = -6 + 4

Reorder the terms:
4 + -4b + b2 = -6 + 4

Combine like terms: -6 + 4 = -2
4 + -4b + b2 = -2

Factor a perfect square on the left side:
(b + -2)(b + -2) = -2

Can't calculate square root of the right side.

The solution to this equation could not be determined.